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5n^2-n-3=3n^2-3
We move all terms to the left:
5n^2-n-3-(3n^2-3)=0
We add all the numbers together, and all the variables
5n^2-1n-(3n^2-3)-3=0
We get rid of parentheses
5n^2-3n^2-1n+3-3=0
We add all the numbers together, and all the variables
2n^2-1n=0
a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4} =1/2 $
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